GregTech 5/Electricity/zh-cn

从5.0版开始（适用于Minecraft 1.7.2），格雷科技开始使用自己的能源网系统，因为GregoriusT并不满足于的能源网系统.

电压与电流
格雷科技使用“电压”（V）和电流（A）两个术语来描述新能源网. 电流为1A等价于一个IC2的EU电力包；电压则是指代这个电力包的大小.

EU/t is the total EU received. For example, if a machine receives one 32V packet and another 24V packet, the total EU/t received is 32 + 24 = 56 EU/t.

Unlike the IC2 energy system, all GregTech energy-interacting blocks have limits on both the Voltage and the Amperage they can interact with.

Different machine blocks accept and emit different Amperages.
 * GregTech will output 1A if used to step-up Voltages and output 4A if used to step-down.
 * input/output 1A per Battery inside.
 * accepting machine blocks accept either 2A or 3A input.
 * Generators output 1A.

You do need to be careful when trying to power machines:
 * Machines that get a higher Voltage than they can handle explode.
 * Excess Amperes fed into machines have no effect as long as the voltage is below the machines' limit.

Machines and recipes each have voltage tiers. The tier of a Multiblock Machine is determined by its. Machine and recipe tiers do interact, and must be paid attention to.

Recipes can be overclocked multiple times if a machine is more than one tier above a recipe's tier.
 * If a recipe has a minimum required voltage within a higher tier than that of the machine, the recipe cannot be carried out.
 * If a recipe has a minimum required voltage within the same tier as the machine, the recipe functions normally.
 * If a recipe has a minimum required voltage within a lower tier than that of the machine, the recipe is overclocked. Overclocked recipes are carried out at double normal speed, double normal total energy, and thus quadruple normal energy per tick.

在5.0版本中，格雷科技有10个电压等级.

备注：ULV算作0级（T0）.

线缆与损耗
Given that GregTech has its own power system now, you will need to use GT cables for powering GT machines. Do note that the only machine capable of accepting IC2 EU in GT is the  (Not to be confused with the IC2 Transformer).

All GT Cables have a max Voltage, max Amperage and a Loss: Do note that packets can rebound. Even if the logical path that a packet dictates that EU should not travel in that direction, you should not take for granted that your cables will not have some stray EU packets travelling through them. For example a 32V package is sent trough a Tin Cable which has a loss of 1EU per block to a machine 8 blocks away. After 8 blocks of cables the 32V Package is down to 24V when it arrives at the machine. Should the machine need for example 30EU/t to operate. A second package sent in the same tick is needed every 4 Ticks. Thus a 2A supply is needed for the machine with this setup. Cable losses are applied to each EU Package, netting you a 2x power loss.
 * Cables that get packets higher than their maximum Voltage will catch fire and melt.
 * Cables that have more Amperes travelling through them than their maximum Amperage limit will catch fire and melt.
 * The loss of a cable is per Block a EU package travels.

Each Material has 1x, 2x, 4x, 8x 12x and 16x uninsulated Wires and 1x, 2x, 4x, 8x and 12x Insulated Cables.

Do note that Uninsulated Wires have 2x the loss as Insulated Cables.

Here is an example:
 * A 1x Tin Cable can handle 1A and 32V at a loss of 1V/m. This means that the EU packet can travel 32 blocks before it dies.
 * A 1x Tin Wire can handle 1A and 32V at a loss of 2V/m. In this case, the EU can travel 18 blocks only.

Below is a table of the current properties of various types of cables in GregTech:

备注：[1]无绝缘版本；[2]暂无合成

Also any GT Block and Battery outputting Energy has an energy loss on output. This means there is no such thing as lossless cables in GregTech.

A power outputting machine will take (8 * 4 ^ Tier) + (2 ^ Tier) EU from its storage and output only (8 * 4 ^ Tier) EU. The energy lost is therefore (2 ^ Tier).

An example: Say a turbine is supposed to output 32V.

output = 32 = (8 * 4 ^ Tier).

Solving for Tier gives you 1. The energy loss will then be (2 ^ Tier). In this case it is 2.

So the turbine takes 34 EU from its storage, outputs 32 and then voids 2 EU per packet output.

Here is a table documenting some of the cable properties in GregTech:

Optimal Cable length between Batteries for maximum efficiency.

The EU loss of GregTech Cables and Batteries scales linearly with the number of sequential Cables and the number of Batteries, but since voltage is topped up at every battery there will be a loss that is increasing exponentially for every identical segment of a Battery and x-number of Cable links. This exponential loss from more batteries also reduces the impact of the linear loss, but this ofc comes at the cost of more exponential loss. This means that there must exist a sweet spot, because with short segments the extra exponential loss of more segments will be more detrimental to the efficiency than the linear loss from making each segment longer, for long segments this will be reversed. So lets do the math!

Lets first define our terms, a segment is the length of a Battery plus a number of sequential Cables. The efficiency of such a segment will be (8 * 4^T - (D - 1)L) / (8 * 4^T + 2^T). T is the tier (ULV is tier 0, LV is tier 1 and so on). L is the loss of the cable in voltage/meter/ampere. D is the distance of the segment, so the length of the Cables plus the battery.

But this is no good since we want to figure out the optimal length when there is an element of exponential decline that we haven't accounted for. We do this by making an expression of how much efficiency we get in each single block if there was a uniform exponential decline over the whole segment. This turns out to be ((8 * 4^T - (D - 1)L) / (8 * 4^T + 2^T))^(1 / D).

We now take the derivative of that expression with respect to D to get how the efficiency changes when we change the length of the segments, when we do this we get such a ghastly monstrosity that not even WolframAlpha can deal with it algebraically. But this wont stop us on our quest for efficiency! Lets solve it numerically!

Step 1: go to http://www.wolframalpha.com/ because we are lazy. Step 2: Enter "(d/dD) ((8 * 4^T - (D - 1)L) / (8 * 4^T + 2^T))^(1 / D) = 0, T=, L=". It will solve the problem numerically for each separate case. So if you want to know the optimal length of Annealed Copper Cable between your MV Batteries, you enter T=2, L=1 and it will give you the optimal length of each segment (This includes the battery!). In the case of Annealed Copper Cable this turns out to be about 24.1, so 23 cables between each battery is optimal. For more information on other cables, see the table above.

机器爆炸
Using GregTech machines without thought and care can be fairly unsafe. If a machine gets contact with rain on any of the 6 sides of the block, it can catch fire. If a machine gets lit on fire, it can explode.

能量转换
GregTech machines does not accept EU from IndustrialCraft² cables and some other mods EU powered blocks does not accept GregTech cables, thus there is the need to convert IC2 EU and GT5 EU back and forth.

To convert IC2 EU into GT5 EU, simply connect (read put directly adjacent) a GT transformer input to an IC2 Energy Source output side. This means connecting the output dot of a IC2 transformer/storage block to the input dot of a GT transformer.

To convert GT5 EU into IC2 EU, simply connect GT cables to IC2 blocks.

Example screenshots of IC2 and GT5 EU conversions: